Optimal. Leaf size=325 \[ -\frac {20 d \sqrt [4]{c+d x}}{21 b^2 (a+b x)^{3/4}}-\frac {4 (c+d x)^{5/4}}{7 b (a+b x)^{7/4}}+\frac {5 \sqrt {2} d^{7/4} \sqrt {b c-a d} ((a+b x) (c+d x))^{3/4} \sqrt {(b c+a d+2 b d x)^2} \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{21 b^{9/4} (a+b x)^{3/4} (c+d x)^{3/4} (b c+a d+2 b d x) \sqrt {(a d+b (c+2 d x))^2}} \]
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Rubi [A]
time = 0.21, antiderivative size = 325, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.210, Rules used = {49, 64, 637,
226} \begin {gather*} \frac {5 \sqrt {2} d^{7/4} \sqrt {b c-a d} ((a+b x) (c+d x))^{3/4} \sqrt {(a d+b c+2 b d x)^2} \left (\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} F\left (2 \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{21 b^{9/4} (a+b x)^{3/4} (c+d x)^{3/4} (a d+b c+2 b d x) \sqrt {(a d+b (c+2 d x))^2}}-\frac {20 d \sqrt [4]{c+d x}}{21 b^2 (a+b x)^{3/4}}-\frac {4 (c+d x)^{5/4}}{7 b (a+b x)^{7/4}} \end {gather*}
Antiderivative was successfully verified.
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Rule 49
Rule 64
Rule 226
Rule 637
Rubi steps
\begin {align*} \int \frac {(c+d x)^{5/4}}{(a+b x)^{11/4}} \, dx &=-\frac {4 (c+d x)^{5/4}}{7 b (a+b x)^{7/4}}+\frac {(5 d) \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/4}} \, dx}{7 b}\\ &=-\frac {20 d \sqrt [4]{c+d x}}{21 b^2 (a+b x)^{3/4}}-\frac {4 (c+d x)^{5/4}}{7 b (a+b x)^{7/4}}+\frac {\left (5 d^2\right ) \int \frac {1}{(a+b x)^{3/4} (c+d x)^{3/4}} \, dx}{21 b^2}\\ &=-\frac {20 d \sqrt [4]{c+d x}}{21 b^2 (a+b x)^{3/4}}-\frac {4 (c+d x)^{5/4}}{7 b (a+b x)^{7/4}}+\frac {\left (5 d^2 ((a+b x) (c+d x))^{3/4}\right ) \int \frac {1}{\left (a c+(b c+a d) x+b d x^2\right )^{3/4}} \, dx}{21 b^2 (a+b x)^{3/4} (c+d x)^{3/4}}\\ &=-\frac {20 d \sqrt [4]{c+d x}}{21 b^2 (a+b x)^{3/4}}-\frac {4 (c+d x)^{5/4}}{7 b (a+b x)^{7/4}}+\frac {\left (20 d^2 ((a+b x) (c+d x))^{3/4} \sqrt {(b c+a d+2 b d x)^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-4 a b c d+(b c+a d)^2+4 b d x^4}} \, dx,x,\sqrt [4]{(a+b x) (c+d x)}\right )}{21 b^2 (a+b x)^{3/4} (c+d x)^{3/4} (b c+a d+2 b d x)}\\ &=-\frac {20 d \sqrt [4]{c+d x}}{21 b^2 (a+b x)^{3/4}}-\frac {4 (c+d x)^{5/4}}{7 b (a+b x)^{7/4}}+\frac {5 \sqrt {2} d^{7/4} \sqrt {b c-a d} ((a+b x) (c+d x))^{3/4} \sqrt {(b c+a d+2 b d x)^2} \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{21 b^{9/4} (a+b x)^{3/4} (c+d x)^{3/4} (b c+a d+2 b d x) \sqrt {(a d+b (c+2 d x))^2}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 10.05, size = 73, normalized size = 0.22 \begin {gather*} -\frac {4 (c+d x)^{5/4} \, _2F_1\left (-\frac {7}{4},-\frac {5}{4};-\frac {3}{4};\frac {d (a+b x)}{-b c+a d}\right )}{7 b (a+b x)^{7/4} \left (\frac {b (c+d x)}{b c-a d}\right )^{5/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.06, size = 0, normalized size = 0.00 \[\int \frac {\left (d x +c \right )^{\frac {5}{4}}}{\left (b x +a \right )^{\frac {11}{4}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (c + d x\right )^{\frac {5}{4}}}{\left (a + b x\right )^{\frac {11}{4}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (c+d\,x\right )}^{5/4}}{{\left (a+b\,x\right )}^{11/4}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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